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Asked: January 21, 20212021-01-21T18:56:16+00:00 2021-01-21T18:56:16+00:00In: MAKAUT

11.(b) Show that in a cubic crystal of side a, the interplaner spacing between consecutive parallel planes of miller indices (hkl) is $d_{hkl} = a / \sqrt{h^2+k^2+l^2}$

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11.(b) Show that in a cubic crystal of side a, the interplaner spacing between consecutive parallel planes of miller indices (hkl) is $d_{hkl} = a / \sqrt{h^2+k^2+l^2}$

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11.(b) Show that in a cubic crystal of side a, the interplaner spacing between consecutive parallel planes of miller indices (hkl) is

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11.(b) Show that in a cubic crystal of side a, the interplaner spacing between consecutive parallel planes of miller indices (hkl) is $d_{hkl} = a / \sqrt{h^2+k^2+l^2}$

Leave an answer
Cancel reply