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7.b) A negative feedback amplifier has the following parameters:
g
g
See less1(i). The Von-Neumann bottleneck is a problem, which occurs due to
speed disparity between CPU and main memory
speed disparity between CPU and main memory
See less1.(i) What is the output of this C code ?
ans:- (c) 3.000000
ans:- (c) 3.000000
See less1(iii). The general solution of p = log ( px – y), Where , is
Ans:- $y=cx - e^c$ Explanation:- p = log(px - y) $\Rightarrow px - y = e^p$ $\Rightarrow y = px - e^p$ $\Rightarrow p = p.1 + x\frac{dp}{dx} -e^p\frac{dp}{dx}$ $\Rightarrow (x-e^p)\frac{dp}{dx} = 0$ $\Rightarrow$ p = c or $x = e^p$ $\therefore$ general solution $y = cx - e^c$
Ans:-
Explanation:-
p = log(px – y)
p = c or
general solution
See less1(iv) In Fraunhofer diffraction the incident wavefront is
a) Plane
a) Plane
See less1(xv). The number of possible arrangements of two fermions in three cells is
c) 3 Explanation: All possible ways of arranging n particles in g phase cells According to Fermions: Number of ways of all possible arrangement = $\frac{g!}{n!(g-n)!}$ here g = 3 and n = 2 So, Number of ways of all possible arrangement = $\frac{3!}{2!(3-2)!}$ = 3
c) 3
Explanation:
All possible ways of arranging n particles in g phase cells
According to Fermions:
Number of ways of all possible arrangement =
here g = 3 and n = 2 So,
Number of ways of all possible arrangement = = 3
See less1(iv). The locus of the centre of curvature is called
b) evolute Explanation: In the differential geometry of curves, the evolute of a curve is the locus of all its centers of curvature. That is to say that when the center of curvature of each point on a curve is drawn, the resultant shape will be the evolute of that curve.
b) evolute
Explanation:
In the differential geometry of curves, the evolute of a curve is the locus of all its centers of curvature. That is to say that when the center of curvature of each point on a curve is drawn, the resultant shape will be the evolute of that curve.
See less8.(c) Given the following, determine the size of the sub fields ( in bits ) in the address for Direct Mapping, associative and Set associative mapping cache schemes :
Mile to batana
Mile to batana
See less1(iv). In order to execute a program instructions must be transferred from memory along a bus to the CPU. If the bus has 8 data lines, at most one 8 bit byte can be transferred at a time. How many memory accesses would be needed in this case to transfer a 32 bit instruction from memory to the CPU?